word problems with linear equations

Topic:-Linear equation

Linear equations can have one or more variables. Linear equations occur with great regularity in applied mathematics. While they arise quite naturally when modeling many phenomena, they are particularly useful since many non-linear equations may be reduced to linear equations by assuming that quantities of interest vary to only a small extent from some "background" state.

Lets see word problems with linear equations

Question:-

A florist charged $15.75 for 6 tulips and 5 irises.The same day the florist charged 12.05 for 7 tulips and 2 irises .Find the cost of 1 tulip and 1 irises.

Answer:-

solving linear equations

Let T as Tulips

 I as irises

and let's make two  linear equations out of the given data .

  6T+5I = 15.75

  7T+2I=12.05

multiply first equation with 2 and second equation with 5

  12T+10I=31.50

  35T+10I=60.25  (subtracting)
--------------------------
  -23T = 28.75

    T = $1.25

6T+5I=15.75

6(1.25)+5I=15.75

7.50+5I=15.75

    5I=8.25

  I=$1.65

So 1 tulip=$1.25 and 1 Irises=$1.65

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