In Euclidean plane geometry, a quadrilateral is a polygon with four sides (or 'edges') and four vertices or corners.
The word quadrilateral is made of the words quad (meaning "four") and lateral (meaning "of sides").
The interior angles of a simple quadrilateral add up to 360 degrees of arc.(Source: From Wikipedia).
Some of the Quadrilateral Properties are
Parallelograms
Square
Rectangle
Rhombus
Trapezoid
Kite
Now, we are going to see the problems on solve the value of quadrilateral.
Various Quadrilateral Formulas Used to Solve the Problem:
Square:
Formula for the perimeter of square= 4*a
Formula for the area of square= a2
Here ‘a’ is the side value of square
Rectangle:
Formula for the area of rectangle=l*b
Perimeter of rectangle=2(l + w)
Where, l is length and w is the width.
Trapezoid:
Formula for the area of trapezoid = (1/2) * h * (a + b)
Where, a and b are the length of the bases and h is the height.
Rhombus:
Formula for the area of rhombus = 1/2 (d1* d2)
Where, d1 and d2 are the diagonal values of the rhombus.
Parallelogram:
Formula for the area of parallelogram = l*b
Where, l is length and b is breadth.
Kite:
Formula for the area of kite = (1/2)*x*y
Where, x and y are the diagonal values of the kite.
My forthcoming post is on Quadratic Formula Solver and Solve for x will give you more understanding about Algebra.
Example Problems on Solve the Value of Quadrilaterals:
Example problem 1:
The two angles of a quadrilateral are equal with degree measure 80° and the third angle is given as 116°. Solve for the fourth angle.
Solution:
The sum of the angles of a quadrilateral = 360°.
Let us take x is the fourth angle
Two angles of the quadrilateral are equal that is 80°
80+80+116+x=360
276+ x = 360
Therefore x = 360 – 276 = 84°
Hence the fourth angle is 84°
Example problem 2:
The area of a rectangular sheet is 600 cm2. If the length of the sheet is 20 cm, what is its width and also solve for the perimeter of the rectangular sheet.
Solution:
Area of the rectangular sheet = 600 cm2
Length (l) = 20 cm
Area of the rectangle = l × b (where b = width of the sheet)
Therefore, width b =Area / l =600 / 20= 30 cm
Perimeter of sheet = 2 × (l + b) = 2 × (20 + 30) cm = 100 cm
So, the width of the rectangular sheet is 30 cm and its perimeter is 100 cm.
Example problem 3:
Solve the area of a square park whose perimeter is 240 m.
Solution:
Formula for the perimeter of the square is 4*a
4*a=240
a = 240 / 4
a = 60m.
Area of the square =a2
=(60)2
=3600m2
So, the side of the square is 60m and area is 3600m2.
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