Lines Rays And Points Names

Line contains two end points is called segment.Line segment expressed with a connected piece of line.line segment named by its endpoints.
A ray contains starting points only but it doesn't have an any ending points. A ray is a part of a line and we draw only a parts of a line and marked with arrow head at it  two ends to represent that rays extends endlessly in both directions.
A point represent a place in a plane with a help of pencil, a point is nothing but the dot, it has no dimension or no width, it’s only a simple black dot. Co ordinates of a point express particular place in a segment for representation.

Having problem with Finding Inflection Points keep reading my upcoming posts, i will try to help you.

Lines Rays and Points Names:
Lines,rays and points names are as follows

Different names of lines:
Parallel line segment:
When two lines does not touch each other are called parallel lines.

Perpendicular line segment:
When two line segment  which form a L shape are called perpendicular lines.
Different names of points:
Collinear points:
Where  three or more points lies on the same line its a collinear points.

Midpoint:
Midpoint has a halfway point where line segment divided into two equal parts are called midpoint.

Equidistant point:
In a line segment where point is equal length from other points which are in congruent then the point is equidistant point.

Rays:
Sun emitting rays of light in all directions. rays of light from torch light shows idea for rays and initial point is a vertex for an angles and the two rays are called arms of the angle.

Problems in Lines Rays and Points Names:
Example 1:
Find the distance between the points A(-8,1) and B (6,3).

Solution:
Let assume "d" be the distance between A and B.           (x1,y1)= (-8,1), (x2,y2)= (6,3).

Then d (A, B) =sqrt((x_2-x_1)^2+(y_2-y_1)^2)

=sqrt((6+8)^2 +(3-1)^2)

= sqrt(14^2+2^2)

=sqrt(196+4)

=sqrt200

=10  sqrt2

Example 2:
Find the mid point co ordinates of the line segment joining given points A(3,-2) and B(-5,4)

Solution:
The required mid point is
Formul a = ((x_1+x_2)/2 ,(y_1+y_2)/2) here, (x1, y1) = (3,-2),(x2, y2) = (-5,4)

= ((3-5)/(2))((4-2)/(2))

= (-2/2)  ,   (2/2)

= (-1,1)

My forthcoming post is on Bayes Theorem Problems and How to Solve Compound Inequalities will give you more understanding about Algebra.

Example 3:

Find the slope of the lines given (5,-1) and (1,3)
Solution:
(x1,y1)= (5,-1), (x2,y2)= (1,3).
We know to find slope of line,m=  (y_2-y_1) /(x_2-x_1)

=(3-(-1))/(1-5)

m =4/-4 = -1

Example 4:

Find the equation of the line having slope -4 and y-intercept 3.
Solution:
Applying the equation of the line is y = mx + c
Given,       m = -4 ,c =3

y = -4 x +3

or  y = -4x+3
or  -4x+y −3 = 0
or   4x-y+3 = 0