In
geometry, a coordinate system is a system which uses a set of numbers,
or coordinates, to uniquely determine the position of a point or other
geometric element. The order of the coordinates is significant and they
are sometimes identified by their position in an ordered tuple and
sometimes by a letter, as in 'the x-coordinate'. In elementary
mathematics the coordinates are taken to be real numbers, but in more
advanced applications coordinates can be taken to be complex numbers.
(Source: Wikipedia)
I like to share this Area of Square with you all through my article.
Area using coordinates problem 1:
Find the area of the square using the coordinates A (3, 4), B (7, 7), C (4, 7), D (7, 11). Dimension in centimeter.
Solution:
First we have to find the distance between the two corners. This distance value is equal to side length of the square.
Formula:
Distance (s) = √ ((x2 – x1)2 + (y2 – y1)2)
Distance between A & B is,
Distance (s) = √ ((7 – 3)2 + (7 - 3)2)
= √ (25)
= 5 cm
Side length of the square is (s) = 5 cm
Area of the square = s2
Substitute the given side length value in the above equation, we get
Area = 25cm2
= 25 cm2
Answer:
The area of square is 25 cm2
Area using coordinates problem 2:
Find the area of the square using the coordinates A (12, 5), B (6, - 3), C (5, 10), D (11, 2). Dimension in centimeter.
Solution:
First we have to find the distance between the two corners. This distance value is equal to side length of the square.
Formula:
Distance (s) = √ ((x2 – x1)2 + (y2 – y1)2)
Distance between A & B is,
Distance (s) = √ ((6 – 12)2 + (- 3 - 5)2)
= √ (100)
= 10 cm
Side length of the square is (s) = 10 cm
Area of the square = s2
Substitute the given side length value in the above equation, we get
Area = 100 cm2
= 100 cm2
Answer:
The area of the square is 100 cm2
Area using coordinates problem 3:
Find the area of the square using the coordinates A (10, 2), B (- 5, 2), C (6, 5), D (18, - 4). Dimension in centimeter.
Solution:
First we have to find the distance between the two corners. This distance value is equal to side length of the square.
Formula:
Distance (s) = √ ((x2 – x1)2 + (y2 – y1)2)
Distance between A & B is,
Distance (s) = √ ((- 5 – 10)2 + (2 - 2)2)
= √ (225)
= 15 cm
Side length of the square is (s) = 15 cm
Area of the square = s2
Substitute the given side length value in the above equation, we get
Area = 152 cm2
= 225 cm2
Answer:
The area of the square is 225 cm2
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Answer:
The final answer is 58 cm2
Area using coordinates problem 2:
Find the area of the square using the coordinates A (3, 7), B (6, - 2), C (9, 2), D (0, 5). Dimension in centimeter.
Answer:
The final answer is 90 cm2
(Source: Wikipedia)
I like to share this Area of Square with you all through my article.
Example problems for area using coordinates
Area using coordinates problem 1:
Find the area of the square using the coordinates A (3, 4), B (7, 7), C (4, 7), D (7, 11). Dimension in centimeter.
Solution:
First we have to find the distance between the two corners. This distance value is equal to side length of the square.
Formula:
Distance (s) = √ ((x2 – x1)2 + (y2 – y1)2)
Distance between A & B is,
Distance (s) = √ ((7 – 3)2 + (7 - 3)2)
= √ (25)
= 5 cm
Side length of the square is (s) = 5 cm
Area of the square = s2
Substitute the given side length value in the above equation, we get
Area = 25cm2
= 25 cm2
Answer:
The area of square is 25 cm2
Area using coordinates problem 2:
Find the area of the square using the coordinates A (12, 5), B (6, - 3), C (5, 10), D (11, 2). Dimension in centimeter.
Solution:
First we have to find the distance between the two corners. This distance value is equal to side length of the square.
Formula:
Distance (s) = √ ((x2 – x1)2 + (y2 – y1)2)
Distance between A & B is,
Distance (s) = √ ((6 – 12)2 + (- 3 - 5)2)
= √ (100)
= 10 cm
Side length of the square is (s) = 10 cm
Area of the square = s2
Substitute the given side length value in the above equation, we get
Area = 100 cm2
= 100 cm2
Answer:
The area of the square is 100 cm2
Area using coordinates problem 3:
Find the area of the square using the coordinates A (10, 2), B (- 5, 2), C (6, 5), D (18, - 4). Dimension in centimeter.
Solution:
First we have to find the distance between the two corners. This distance value is equal to side length of the square.
Formula:
Distance (s) = √ ((x2 – x1)2 + (y2 – y1)2)
Distance between A & B is,
Distance (s) = √ ((- 5 – 10)2 + (2 - 2)2)
= √ (225)
= 15 cm
Side length of the square is (s) = 15 cm
Area of the square = s2
Substitute the given side length value in the above equation, we get
Area = 152 cm2
= 225 cm2
Answer:
The area of the square is 225 cm2
My forthcoming post is on Mean Median Mode Examples, puc board karnataka will give you more understanding about Algebra
Practice problems for area using coordinates
Find the area of the square using the coordinates A (- 5, - 6), B (2, - 3), C (9, -1), D (2, 2). Dimension in centimeter.Answer:
The final answer is 58 cm2
Area using coordinates problem 2:
Find the area of the square using the coordinates A (3, 7), B (6, - 2), C (9, 2), D (0, 5). Dimension in centimeter.
Answer:
The final answer is 90 cm2
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