Introduction for Rectangle Area and Perimeter:
In mathematics, shapes play an important role. Basically, a polygon with 4 sides is said to be quadrilateral. Rectangle is one of the quadrilaterals with 4 equal angles all with 90degree. Opposite sides of rectangle is always equal. In this article, we shall discuss about area and perimeter of rectangle. Also we shall solve some sample problems regarding area and perimeter of rectangle.
Having problem with Area Cylinder keep reading my upcoming posts, i will try to help you.

Area:
Area of Rectangle = length * breadth
In simple, Area of rectangle = l * b
Example for finding the area of the rectangle:
Calculate the area of the rectangle whose length is 12cm and breadth 5cm
Solution:
Given Length = 12 cm
Breadth = 5 cm
Formula: Area of rectangle = length * breadth
= 12 * 5
Area of Rectangle = 60 cm2
Perimeter:
Perimeter of Rectangle = 2(length + breadth)
In Simple, Perimeter of Rectangle = 2( l + b )
Example for finding the perimeter of the rectangle:
Calculate the perimeter of the rectangle whose length is 18cm and breadth 7cm
Solution:
Given: Length = 18 cm
Breadth = 7 cm
Formula: Perimeter of rectangle = 2(length + breadth)
= 2 (18 + 7)
= 2 (25)
Perimeter of Rectangle = 50 cm
In this article we learnt about calculating area and perimeter of rectangle
Problems 1: Solve the area and perimeter of a rectangle whose length is 8m and breadth is 70 cm.
Solution:
Length of the rectangle, l = 8 m or 800 cm
Breadth of the rectangle, b = 70 cm
(a) Area of the rectangle, A = l × b
= 800 cm × 70 cm
Area = 56000 sq.cm.
(b) Perimeter of the rectangle, P = 2l + 2b
= 2 × 800 cm + 2 × 70 cm
= 1600 cm + 140 cm
Perimeter = 1740 cm
Algebra is widely used in day to day activities watch out for my forthcoming posts on Circle Equation and cbse xth syllabus. I am sure they will be helpful.
Problem 2: Solve the area and perimeter of a rectangle whose length is 83m and breadth is 100 cm.
Solution:
Length of the rectangle, l = 83 cm
Breadth of the rectangle, b = 100 cm
(a) Area of the rectangle, A = l × b
= 83 cm × 100 cm
Area = 8300 sq.cm.
(b) Perimeter of the rectangle, P = 2l + 2b
= 2 × 83 cm + 2 × 100 cm
= 166 cm + 200 cm
Perimeter = 366 cm.
Practice Problems:
Answer: length 64001, breadth 25600
In mathematics, shapes play an important role. Basically, a polygon with 4 sides is said to be quadrilateral. Rectangle is one of the quadrilaterals with 4 equal angles all with 90degree. Opposite sides of rectangle is always equal. In this article, we shall discuss about area and perimeter of rectangle. Also we shall solve some sample problems regarding area and perimeter of rectangle.
Having problem with Area Cylinder keep reading my upcoming posts, i will try to help you.
- A rectangle is a four-sided polygon.
- The opposite sides are parallel and of equal length.
- Opposite angles are equal to 90 degree.
- Diagonals are equal and bisect each other.
Area and Perimeter of Rectangle:
Area:
Area of Rectangle = length * breadth
In simple, Area of rectangle = l * b
- The rectangle’s area can be manipulated by multiplying the base times the altitude.
- For example, if a rectangle has a base of length 5 inches and a height of 3 inches, its area is 5 * 3 = 15 square inches
- Area is deliberated in square units such as square inches, square feet or square meters.
Example for finding the area of the rectangle:
Calculate the area of the rectangle whose length is 12cm and breadth 5cm
Given Length = 12 cm
Breadth = 5 cm
Formula: Area of rectangle = length * breadth
= 12 * 5
Area of Rectangle = 60 cm2
Perimeter:
Perimeter of Rectangle = 2(length + breadth)
In Simple, Perimeter of Rectangle = 2( l + b )
- The perimeter of a rectangle is the length around the exterior of the rectangle.
- A rectangle has four sides with opposite sides being similar.
- The formula for calculating the perimeter is Side A + Side B + Side A + Side B.
- This can be simplified as 2 * Side A + 2 * Side B or 2 * (Side A + Side B)
Example for finding the perimeter of the rectangle:
Calculate the perimeter of the rectangle whose length is 18cm and breadth 7cm
Given: Length = 18 cm
Breadth = 7 cm
Formula: Perimeter of rectangle = 2(length + breadth)
= 2 (18 + 7)
= 2 (25)
Perimeter of Rectangle = 50 cm
In this article we learnt about calculating area and perimeter of rectangle
Problems:
Problems 1: Solve the area and perimeter of a rectangle whose length is 8m and breadth is 70 cm.
Solution:
Length of the rectangle, l = 8 m or 800 cm
Breadth of the rectangle, b = 70 cm
(a) Area of the rectangle, A = l × b
= 800 cm × 70 cm
Area = 56000 sq.cm.
(b) Perimeter of the rectangle, P = 2l + 2b
= 2 × 800 cm + 2 × 70 cm
= 1600 cm + 140 cm
Perimeter = 1740 cm
Algebra is widely used in day to day activities watch out for my forthcoming posts on Circle Equation and cbse xth syllabus. I am sure they will be helpful.
Problem 2: Solve the area and perimeter of a rectangle whose length is 83m and breadth is 100 cm.
Solution:
Length of the rectangle, l = 83 cm
Breadth of the rectangle, b = 100 cm
(a) Area of the rectangle, A = l × b
= 83 cm × 100 cm
Area = 8300 sq.cm.
(b) Perimeter of the rectangle, P = 2l + 2b
= 2 × 83 cm + 2 × 100 cm
= 166 cm + 200 cm
Perimeter = 366 cm.
Practice Problems:
- Find the cost of fencing a rectangular park of length 170 m and breadth 100 m at the rate of Rs.5 per meter.
- Solve the area and perimeter of a rectangle whose length is 64m and breadth is 100 cm.
Answer: length 64001, breadth 25600
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